go 父子集组装成树形结构体
import ( "encoding/json" "fmt" ) type Row struct { Id int ParentId int Name string } type Node struct { *Row Children []*Node `json:"children,omitempty"` } func generateTree(rows []*Row) []*Node { idMap := make(map[int]*Node, len(rows)+1) topNode := &Node{Row: &Row{Id: 0, ParentId: 0, Name: "root"}} idMap[topNode.Id] = topNode for _, row := range rows { // 先判断 当前ID 对应的节点是否存在 nNode, ok := idMap[row.Id] if ok { // 存在就补录节点数据 nNode.Row = row } else { // 不存在就新建一个节点,并放入map nNode = &Node{Row: row} idMap[nNode.Id] = nNode } // 根据parentId 获取 parentNode pNode, ok := idMap[nNode.ParentId] if !ok { // 获取不到,说明父节点还没有,先进行添加 pNode = &Node{} idMap[nNode.ParentId] = pNode } // 将当前节点添加到父节点的 array 中 pNode.Children = append(pNode.Children, nNode) } return topNode.Children } func main() { data := []*Row{ {Id: 2, ParentId: 1, Name: "java开发"}, {Id: 7, ParentId: 3, Name: "python书"}, {Id: 3, ParentId: 1, Name: "python开发"}, {Id: 5, ParentId: 4, Name: "水果销售"}, {Id: 6, ParentId: 4, Name: "蔬菜销售"}, {Id: 1, ParentId: 0, Name: "开发菜单"}, {Id: 4, ParentId: 0, Name: "销售菜单"}, } tree := generateTree(data) marshal, err := json.MarshalIndent(tree, "", " ") //marshal, err := json.Marshal(tree) if err != nil { panic(err) } //fmt.Println(string(marshal)) fmt.Printf("%s\n", marshal) }
返回值
[ { "Id": 1, "ParentId": 0, "Name": "开发菜单", "children": [ { "Id": 2, "ParentId": 1, "Name": "java开发" }, { "Id": 3, "ParentId": 1, "Name": "python开发", "children": [ { "Id": 7, "ParentId": 3, "Name": "python书" } ] } ] }, { "Id": 4, "ParentId": 0, "Name": "销售菜单", "children": [ { "Id": 5, "ParentId": 4, "Name": "水果销售" }, { "Id": 6, "ParentId": 4, "Name": "蔬菜销售" } ] } ]
版权声明:
作者:超级管理员
链接:
https://blog.apecloud.ltd/article/detail.html?id=go-list-to-tree
来源:猿码云个人技术站
文章版权归作者所有,未经允许请勿转载。
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